Base | Representation |
---|---|
bin | 10110001010110011100… |
… | …001110010000011001001 |
3 | 12101122020111001210101121 |
4 | 112022303201302003021 |
5 | 144424441140301301 |
6 | 3123504304315241 |
7 | 215031011513143 |
oct | 26126341620311 |
9 | 5348214053347 |
10 | 1523430400201 |
11 | 5380a08218a6 |
12 | 207301912b21 |
13 | b08746cc238 |
14 | 53a3d393c93 |
15 | 299643753a1 |
hex | 162b38720c9 |
1523430400201 has 32 divisors (see below), whose sum is σ = 1704243490560. Its totient is φ = 1353315465216.
The previous prime is 1523430400187. The next prime is 1523430400207. The reversal of 1523430400201 is 1020040343251.
It is a cyclic number.
It is not a de Polignac number, because 1523430400201 - 213 = 1523430392009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1523430400207) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 388925895 + ... + 388929811.
It is an arithmetic number, because the mean of its divisors is an integer number (53257609080).
Almost surely, 21523430400201 is an apocalyptic number.
It is an amenable number.
1523430400201 is a deficient number, since it is larger than the sum of its proper divisors (180813090359).
1523430400201 is a wasteful number, since it uses less digits than its factorization.
1523430400201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8113.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 1523430400201 its reverse (1020040343251), we get a palindrome (2543470743452).
The spelling of 1523430400201 in words is "one trillion, five hundred twenty-three billion, four hundred thirty million, four hundred thousand, two hundred one".
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