Base | Representation |
---|---|
bin | 11100011001000000… |
… | …00000100101100101 |
3 | 1110100020201001202120 |
4 | 32030200000211211 |
5 | 222203434300031 |
6 | 11000243100153 |
7 | 1046466511326 |
oct | 161440004545 |
9 | 43306631676 |
10 | 15242103141 |
11 | 6511851761 |
12 | 2b54671659 |
13 | 158ba55255 |
14 | a4844644d |
15 | 5e31d8a96 |
hex | 38c800965 |
15242103141 has 4 divisors (see below), whose sum is σ = 20322804192. Its totient is φ = 10161402092.
The previous prime is 15242103137. The next prime is 15242103167. The reversal of 15242103141 is 14130124251.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14130124251 = 3 ⋅4710041417.
It is a cyclic number.
It is not a de Polignac number, because 15242103141 - 22 = 15242103137 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15242103641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2540350521 + ... + 2540350526.
It is an arithmetic number, because the mean of its divisors is an integer number (5080701048).
Almost surely, 215242103141 is an apocalyptic number.
It is an amenable number.
15242103141 is a deficient number, since it is larger than the sum of its proper divisors (5080701051).
15242103141 is an equidigital number, since it uses as much as digits as its factorization.
15242103141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5080701050.
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 15242103141 its reverse (14130124251), we get a palindrome (29372227392).
The spelling of 15242103141 in words is "fifteen billion, two hundred forty-two million, one hundred three thousand, one hundred forty-one".
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