Search a number
-
+
152487713953 is a prime number
BaseRepresentation
bin1000111000000011111…
…0011101110010100001
3112120121010112110212101
42032000332131302201
54444243323321303
6154015112530401
714005534116421
oct2160076356241
9476533473771
10152487713953
11597403804a3
12256779b0a01
13114c1a99653
147547d24481
153e771ced1d
hex2380f9dca1

152487713953 has 2 divisors, whose sum is σ = 152487713954. Its totient is φ = 152487713952.

The previous prime is 152487713921. The next prime is 152487713969. The reversal of 152487713953 is 359317784251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79853151889 + 72634562064 = 282583^2 + 269508^2 .

It is a cyclic number.

It is not a de Polignac number, because 152487713953 - 25 = 152487713921 is a prime.

It is a super-2 number, since 2×1524877139532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 152487713894 and 152487713903.

It is not a weakly prime, because it can be changed into another prime (152487713453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76243856976 + 76243856977.

It is an arithmetic number, because the mean of its divisors is an integer number (76243856977).

Almost surely, 2152487713953 is an apocalyptic number.

It is an amenable number.

152487713953 is a deficient number, since it is larger than the sum of its proper divisors (1).

152487713953 is an equidigital number, since it uses as much as digits as its factorization.

152487713953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6350400, while the sum is 55.

The spelling of 152487713953 in words is "one hundred fifty-two billion, four hundred eighty-seven million, seven hundred thirteen thousand, nine hundred fifty-three".