Base | Representation |
---|---|
bin | 11100011001111101… |
… | …00110000110011001 |
3 | 1110100210210102100111 |
4 | 32030332212012121 |
5 | 222213012333423 |
6 | 11001131004321 |
7 | 1046624614333 |
oct | 161476460631 |
9 | 43323712314 |
10 | 15250121113 |
11 | 6516328787 |
12 | 2b572996a1 |
13 | 1590601906 |
14 | a49532453 |
15 | 5e3c6e60d |
hex | 38cfa6199 |
15250121113 has 2 divisors, whose sum is σ = 15250121114. Its totient is φ = 15250121112.
The previous prime is 15250121101. The next prime is 15250121143. The reversal of 15250121113 is 31112105251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12492085824 + 2758035289 = 111768^2 + 52517^2 .
It is an emirp because it is prime and its reverse (31112105251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15250121113 - 213 = 15250112921 is a prime.
It is a super-2 number, since 2×152501211132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15250121143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7625060556 + 7625060557.
It is an arithmetic number, because the mean of its divisors is an integer number (7625060557).
Almost surely, 215250121113 is an apocalyptic number.
It is an amenable number.
15250121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
15250121113 is an equidigital number, since it uses as much as digits as its factorization.
15250121113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 15250121113 its reverse (31112105251), we get a palindrome (46362226364).
The spelling of 15250121113 in words is "fifteen billion, two hundred fifty million, one hundred twenty-one thousand, one hundred thirteen".
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