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152521310143313 is a prime number
BaseRepresentation
bin100010101011011110100010…
…100000110000001101010001
3202000000220011100022210122022
4202223132202200300031101
5124442402120344041223
61300215153402421225
744061205151312606
oct4253364240601521
9660026140283568
10152521310143313
1144663a19398631
121513379a201815
13671490c1a27b7
1429940dc3b66ad
151297668d01ac8
hex8ab7a2830351

152521310143313 has 2 divisors, whose sum is σ = 152521310143314. Its totient is φ = 152521310143312.

The previous prime is 152521310143291. The next prime is 152521310143339. The reversal of 152521310143313 is 313341013125251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108666280673344 + 43855029469969 = 10424312^2 + 6622313^2 .

It is an emirp because it is prime and its reverse (313341013125251) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152521310143313 is a prime.

It is not a weakly prime, because it can be changed into another prime (152521310143913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76260655071656 + 76260655071657.

It is an arithmetic number, because the mean of its divisors is an integer number (76260655071657).

Almost surely, 2152521310143313 is an apocalyptic number.

It is an amenable number.

152521310143313 is a deficient number, since it is larger than the sum of its proper divisors (1).

152521310143313 is an equidigital number, since it uses as much as digits as its factorization.

152521310143313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 152521310143313 its reverse (313341013125251), we get a palindrome (465862323268564).

The spelling of 152521310143313 in words is "one hundred fifty-two trillion, five hundred twenty-one billion, three hundred ten million, one hundred forty-three thousand, three hundred thirteen".