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152535433 is a prime number
BaseRepresentation
bin10010001011110…
…00000110001001
3101122000121021111
421011320012021
5303022113213
623045210321
73531346501
oct1105700611
9348017244
10152535433
1179114146
12431009a1
13257a8c6b
1416388a01
15d5d0a3d
hex9178189

152535433 has 2 divisors, whose sum is σ = 152535434. Its totient is φ = 152535432.

The previous prime is 152535421. The next prime is 152535437. The reversal of 152535433 is 334535251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115605504 + 36929929 = 10752^2 + 6077^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152535433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 152535395 and 152535404.

It is not a weakly prime, because it can be changed into another prime (152535437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76267716 + 76267717.

It is an arithmetic number, because the mean of its divisors is an integer number (76267717).

Almost surely, 2152535433 is an apocalyptic number.

It is an amenable number.

152535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

152535433 is an equidigital number, since it uses as much as digits as its factorization.

152535433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27000, while the sum is 31.

The square root of 152535433 is about 12350.5235921397. The cubic root of 152535433 is about 534.3062402460.

The spelling of 152535433 in words is "one hundred fifty-two million, five hundred thirty-five thousand, four hundred thirty-three".