Base | Representation |
---|---|
bin | 11100011010011100… |
… | …10010001110011101 |
3 | 1110101002112101012010 |
4 | 32031032102032131 |
5 | 222220040442023 |
6 | 11001355101433 |
7 | 1050004564314 |
oct | 161516221635 |
9 | 43332471163 |
10 | 15254234013 |
11 | 6518687877 |
12 | 2b58741879 |
13 | 1591411995 |
14 | a49cc327b |
15 | 5e42d3093 |
hex | 38d39239d |
15254234013 has 4 divisors (see below), whose sum is σ = 20338978688. Its totient is φ = 10169489340.
The previous prime is 15254234003. The next prime is 15254234029. The reversal of 15254234013 is 31043245251.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31043245251 = 3 ⋅10347748417.
It is not a de Polignac number, because 15254234013 - 24 = 15254233997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15254234003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2542372333 + ... + 2542372338.
It is an arithmetic number, because the mean of its divisors is an integer number (5084744672).
Almost surely, 215254234013 is an apocalyptic number.
It is an amenable number.
15254234013 is a deficient number, since it is larger than the sum of its proper divisors (5084744675).
15254234013 is an equidigital number, since it uses as much as digits as its factorization.
15254234013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5084744674.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 15254234013 its reverse (31043245251), we get a palindrome (46297479264).
The spelling of 15254234013 in words is "fifteen billion, two hundred fifty-four million, two hundred thirty-four thousand, thirteen".
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