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152551431401 = 433547707707
BaseRepresentation
bin1000111000010011000…
…1100001110011101001
3112120202120102122202212
42032010301201303221
54444411131301101
6154025310334505
714010236525525
oct2160461416351
9476676378685
10152551431401
1159773340346
12256951ba435
1311502048695
14755258cd85
153e7cab91bb
hex2384c61ce9

152551431401 has 4 divisors (see below), whose sum is σ = 156099139152. Its totient is φ = 149003723652.

The previous prime is 152551431391. The next prime is 152551431419. The reversal of 152551431401 is 104134155251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 152551431401 - 26 = 152551431337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (152551431001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1773853811 + ... + 1773853896.

It is an arithmetic number, because the mean of its divisors is an integer number (39024784788).

Almost surely, 2152551431401 is an apocalyptic number.

It is an amenable number.

152551431401 is a deficient number, since it is larger than the sum of its proper divisors (3547707751).

152551431401 is an equidigital number, since it uses as much as digits as its factorization.

152551431401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3547707750.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 152551431401 its reverse (104134155251), we get a palindrome (256685586652).

The spelling of 152551431401 in words is "one hundred fifty-two billion, five hundred fifty-one million, four hundred thirty-one thousand, four hundred one".

Divisors: 1 43 3547707707 152551431401