Base | Representation |
---|---|
bin | 1000111000010011000… |
… | …1100001110011011111 |
3 | 112120202120102122202111 |
4 | 2032010301201303133 |
5 | 4444411131301031 |
6 | 154025310334451 |
7 | 14010236525512 |
oct | 2160461416337 |
9 | 476676378674 |
10 | 152551431391 |
11 | 59773340337 |
12 | 256951ba427 |
13 | 11502048688 |
14 | 755258cd79 |
15 | 3e7cab91b1 |
hex | 2384c61cdf |
152551431391 has 2 divisors, whose sum is σ = 152551431392. Its totient is φ = 152551431390.
The previous prime is 152551431359. The next prime is 152551431419. The reversal of 152551431391 is 193134155251.
152551431391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152551431391 - 25 = 152551431359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152551431301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76275715695 + 76275715696.
It is an arithmetic number, because the mean of its divisors is an integer number (76275715696).
Almost surely, 2152551431391 is an apocalyptic number.
152551431391 is a deficient number, since it is larger than the sum of its proper divisors (1).
152551431391 is an equidigital number, since it uses as much as digits as its factorization.
152551431391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 81000, while the sum is 40.
The spelling of 152551431391 in words is "one hundred fifty-two billion, five hundred fifty-one million, four hundred thirty-one thousand, three hundred ninety-one".
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