Base | Representation |
---|---|
bin | 11100011010100100… |
… | …00111110111001001 |
3 | 1110101011102111022222 |
4 | 32031102013313021 |
5 | 222220320141022 |
6 | 11001432423425 |
7 | 1050016254524 |
oct | 161522076711 |
9 | 43334374288 |
10 | 15255240137 |
11 | 6519204785 |
12 | 2b58b47b75 |
13 | 15916a4917 |
14 | a4a0a5bbb |
15 | 5e4431242 |
hex | 38d487dc9 |
15255240137 has 2 divisors, whose sum is σ = 15255240138. Its totient is φ = 15255240136.
The previous prime is 15255240073. The next prime is 15255240233. The reversal of 15255240137 is 73104255251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13561999936 + 1693240201 = 116456^2 + 41149^2 .
It is a cyclic number.
It is not a de Polignac number, because 15255240137 - 26 = 15255240073 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15255240097 and 15255240106.
It is not a weakly prime, because it can be changed into another prime (15255240437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7627620068 + 7627620069.
It is an arithmetic number, because the mean of its divisors is an integer number (7627620069).
Almost surely, 215255240137 is an apocalyptic number.
It is an amenable number.
15255240137 is a deficient number, since it is larger than the sum of its proper divisors (1).
15255240137 is an equidigital number, since it uses as much as digits as its factorization.
15255240137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 35.
Adding to 15255240137 its reverse (73104255251), we get a palindrome (88359495388).
The spelling of 15255240137 in words is "fifteen billion, two hundred fifty-five million, two hundred forty thousand, one hundred thirty-seven".
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