Search a number
-
+
15264131 is a prime number
BaseRepresentation
bin111010001110…
…100110000011
31001201111110012
4322032212003
512401423011
61303055135
7243512561
oct72164603
931644405
1015264131
118686193
1251414ab
13321593c
142054a31
151517a8b
hexe8e983

15264131 has 2 divisors, whose sum is σ = 15264132. Its totient is φ = 15264130.

The previous prime is 15264107. The next prime is 15264149. The reversal of 15264131 is 13146251.

15264131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15264131 is a prime.

It is a super-2 number, since 2×152641312 = 465987390370322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 15264097 and 15264106.

It is not a weakly prime, because it can be changed into another prime (15264101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7632065 + 7632066.

It is an arithmetic number, because the mean of its divisors is an integer number (7632066).

Almost surely, 215264131 is an apocalyptic number.

15264131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15264131 is an equidigital number, since it uses as much as digits as its factorization.

15264131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

The square root of 15264131 is about 3906.9337081655. The cubic root of 15264131 is about 248.0603553675.

The spelling of 15264131 in words is "fifteen million, two hundred sixty-four thousand, one hundred thirty-one".