Base | Representation |
---|---|
bin | 100010110010000011100101… |
… | …011011001110001010011111 |
3 | 202001122010002120022012000222 |
4 | 202302003211123032022133 |
5 | 130022304013002121303 |
6 | 1301203002314111555 |
7 | 44135651364443033 |
oct | 4262034533161237 |
9 | 661563076265028 |
10 | 152973404332703 |
11 | 44818724812509 |
12 | 151a732b71b5bb |
13 | 674843a3b5976 |
14 | 29abd490821c3 |
15 | 12a42c8d5a938 |
hex | 8b20e56ce29f |
152973404332703 has 4 divisors (see below), whose sum is σ = 153078252452280. Its totient is φ = 152868556213128.
The previous prime is 152973404332669. The next prime is 152973404332751. The reversal of 152973404332703 is 307233404379251.
152973404332703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 152973404332703 - 222 = 152973400138399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152973404382703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52424057600 + ... + 52424060517.
It is an arithmetic number, because the mean of its divisors is an integer number (38269563113070).
Almost surely, 2152973404332703 is an apocalyptic number.
152973404332703 is a deficient number, since it is larger than the sum of its proper divisors (104848119577).
152973404332703 is a wasteful number, since it uses less digits than its factorization.
152973404332703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104848119576.
The product of its (nonzero) digits is 11430720, while the sum is 53.
The spelling of 152973404332703 in words is "one hundred fifty-two trillion, nine hundred seventy-three billion, four hundred four million, three hundred thirty-two thousand, seven hundred three".
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