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153003312113 is a prime number
BaseRepresentation
bin1000111001111110110…
…1010100001111110001
3112121221001201120120112
42032133231110033301
510001322321441423
6154142211551105
714024364460151
oct2163755241761
9477831646515
10153003312113
1159985420a83
12257a05bb495
1311574853412
1475965ba761
153ea75c9a78
hex239fb543f1

153003312113 has 2 divisors, whose sum is σ = 153003312114. Its totient is φ = 153003312112.

The previous prime is 153003312097. The next prime is 153003312151. The reversal of 153003312113 is 311213300351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152984241424 + 19070689 = 391132^2 + 4367^2 .

It is a cyclic number.

It is not a de Polignac number, because 153003312113 - 24 = 153003312097 is a prime.

It is not a weakly prime, because it can be changed into another prime (153006312113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76501656056 + 76501656057.

It is an arithmetic number, because the mean of its divisors is an integer number (76501656057).

Almost surely, 2153003312113 is an apocalyptic number.

It is an amenable number.

153003312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

153003312113 is an equidigital number, since it uses as much as digits as its factorization.

153003312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 153003312113 its reverse (311213300351), we get a palindrome (464216612464).

The spelling of 153003312113 in words is "one hundred fifty-three billion, three million, three hundred twelve thousand, one hundred thirteen".