Base | Representation |
---|---|
bin | 11100100000001001… |
… | …01101011000000111 |
3 | 1110111102111221211202 |
4 | 32100010231120013 |
5 | 222314311233211 |
6 | 11010224053115 |
7 | 1051125216335 |
oct | 162004553007 |
9 | 43442457752 |
10 | 15302055431 |
11 | 654267a803 |
12 | 2b7076419b |
13 | 159b2b6590 |
14 | a523b0b55 |
15 | 5e85cc53b |
hex | 39012d607 |
15302055431 has 8 divisors (see below), whose sum is σ = 16790064480. Its totient is φ = 13858464672.
The previous prime is 15302055427. The next prime is 15302055451. The reversal of 15302055431 is 13455020351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 15302055431 - 22 = 15302055427 is a prime.
It is a super-2 number, since 2×153020554312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15302055394 and 15302055403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15302055451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11103851 + ... + 11105228.
It is an arithmetic number, because the mean of its divisors is an integer number (2098758060).
Almost surely, 215302055431 is an apocalyptic number.
15302055431 is a deficient number, since it is larger than the sum of its proper divisors (1488009049).
15302055431 is a wasteful number, since it uses less digits than its factorization.
15302055431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22209145.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 15302055431 its reverse (13455020351), we get a palindrome (28757075782).
The spelling of 15302055431 in words is "fifteen billion, three hundred two million, fifty-five thousand, four hundred thirty-one".
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