Base | Representation |
---|---|
bin | 100010110010111000101000… |
… | …100100110111111110000011 |
3 | 202001211120010021210212211210 |
4 | 202302320220210313332003 |
5 | 130024222142032332210 |
6 | 1301245102425541203 |
7 | 44143036054456620 |
oct | 4262705044677603 |
9 | 661746107725753 |
10 | 153030365511555 |
11 | 4483a8a4924234 |
12 | 151b6387944803 |
13 | 67509173b851c |
14 | 29b09d0105347 |
15 | 12a5a0e8ebe20 |
hex | 8b2e28937f83 |
153030365511555 has 32 divisors (see below), whose sum is σ = 282030315945984. Its totient is φ = 69405898052736.
The previous prime is 153030365511547. The next prime is 153030365511557. The reversal of 153030365511555 is 555115563030351.
153030365511555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 153030365511555 - 23 = 153030365511547 is a prime.
It is not an unprimeable number, because it can be changed into a prime (153030365511557) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5737908132 + ... + 5737934801.
It is an arithmetic number, because the mean of its divisors is an integer number (8813447373312).
Almost surely, 2153030365511555 is an apocalyptic number.
153030365511555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153030365511555 is a deficient number, since it is larger than the sum of its proper divisors (128999950434429).
153030365511555 is a wasteful number, since it uses less digits than its factorization.
153030365511555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11475843075.
The product of its (nonzero) digits is 2531250, while the sum is 48.
The spelling of 153030365511555 in words is "one hundred fifty-three trillion, thirty billion, three hundred sixty-five million, five hundred eleven thousand, five hundred fifty-five".
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