Base | Representation |
---|---|
bin | 100010110010111000101000… |
… | …100100110111111110000010 |
3 | 202001211120010021210212211202 |
4 | 202302320220210313332002 |
5 | 130024222142032332204 |
6 | 1301245102425541202 |
7 | 44143036054456616 |
oct | 4262705044677602 |
9 | 661746107725752 |
10 | 153030365511554 |
11 | 4483a8a4924233 |
12 | 151b6387944802 |
13 | 67509173b851b |
14 | 29b09d0105346 |
15 | 12a5a0e8ebe1e |
hex | 8b2e28937f82 |
153030365511554 has 16 divisors (see below), whose sum is σ = 255840239556000. Its totient is φ = 68224063881024.
The previous prime is 153030365511547. The next prime is 153030365511557. The reversal of 153030365511554 is 455115563030351.
It is a super-2 number, since 2×1530303655115542 (a number of 29 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 153030365511499 and 153030365511508.
It is not an unprimeable number, because it can be changed into a prime (153030365511557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118444554704 + ... + 118444555995.
It is an arithmetic number, because the mean of its divisors is an integer number (15990014972250).
Almost surely, 2153030365511554 is an apocalyptic number.
153030365511554 is a deficient number, since it is larger than the sum of its proper divisors (102809874044446).
153030365511554 is a wasteful number, since it uses less digits than its factorization.
153030365511554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 236889110737.
The product of its (nonzero) digits is 2025000, while the sum is 47.
The spelling of 153030365511554 in words is "one hundred fifty-three trillion, thirty billion, three hundred sixty-five million, five hundred eleven thousand, five hundred fifty-four".
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