Search a number
-
+
153052411481 is a prime number
BaseRepresentation
bin1000111010001010100…
…0100111011001011001
3112122001111010002020122
42032202220213121121
510001422404131411
6154151124203025
714025532014044
oct2164250473131
9478044102218
10153052411481
1159a00107072
12257b4b39475
1311581a848b8
14759cd1bc5b
153eaba779db
hex23a2a27659

153052411481 has 2 divisors, whose sum is σ = 153052411482. Its totient is φ = 153052411480.

The previous prime is 153052411441. The next prime is 153052411487. The reversal of 153052411481 is 184114250351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 149853377881 + 3199033600 = 387109^2 + 56560^2 .

It is an emirp because it is prime and its reverse (184114250351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153052411481 - 26 = 153052411417 is a prime.

It is a super-2 number, since 2×1530524114812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (153052411487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76526205740 + 76526205741.

It is an arithmetic number, because the mean of its divisors is an integer number (76526205741).

Almost surely, 2153052411481 is an apocalyptic number.

It is an amenable number.

153052411481 is a deficient number, since it is larger than the sum of its proper divisors (1).

153052411481 is an equidigital number, since it uses as much as digits as its factorization.

153052411481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 35.

The spelling of 153052411481 in words is "one hundred fifty-three billion, fifty-two million, four hundred eleven thousand, four hundred eighty-one".