153102113 has 2 divisors, whose sum is σ = 153102114. Its totient is φ = 153102112.

The previous prime is 153102091. The next prime is 153102139. The reversal of 153102113 is 311201351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152967424 + 134689 = 12368^2 + 367^2 .

It is an emirp because it is prime and its reverse (311201351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153102113 - 2¹⁶ = 153036577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153102091 and 153102100.

It is not a weakly prime, because it can be changed into another prime (153102143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76551056 + 76551057.

It is an arithmetic number, because the mean of its divisors is an integer number (76551057).

Almost surely, 2^153102113 is an apocalyptic number.

It is an amenable number.

153102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

153102113 is an equidigital number, since it uses as much as digits as its factorization.

153102113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 153102113 is about 12373.4438617549. The cubic root of 153102113 is about 534.9670844745.

Adding to 153102113 its reverse (311201351), we get a palindrome (464303464).

The spelling of 153102113 in words is "one hundred fifty-three million, one hundred two thousand, one hundred thirteen".