Base | Representation |
---|---|
bin | 100010110100001110010001… |
… | …000101010010110001101010 |
3 | 202002011100110021112001122020 |
4 | 202310032101011102301222 |
5 | 130032223444131404032 |
6 | 1301355230343005310 |
7 | 44152502443520160 |
oct | 4264162105226152 |
9 | 662140407461566 |
10 | 153122313153642 |
11 | 44875898980688 |
12 | 15210168a39836 |
13 | 67594ab882431 |
14 | 29b523394d230 |
15 | 12a80e1c47b2c |
hex | 8b4391152c6a |
153122313153642 has 32 divisors (see below), whose sum is σ = 350013626184192. Its totient is φ = 43746761386224.
The previous prime is 153122313153619. The next prime is 153122313153671. The reversal of 153122313153642 is 246351313221351.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is a junction number, because it is equal to n+sod(n) for n = 153122313153594 and 153122313153603.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102203428 + ... + 103690815.
It is an arithmetic number, because the mean of its divisors is an integer number (10937925818256).
Almost surely, 2153122313153642 is an apocalyptic number.
153122313153642 is an abundant number, since it is smaller than the sum of its proper divisors (196891313030550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
153122313153642 is a wasteful number, since it uses less digits than its factorization.
153122313153642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205911962.
The product of its digits is 388800, while the sum is 42.
Adding to 153122313153642 its reverse (246351313221351), we get a palindrome (399473626374993).
The spelling of 153122313153642 in words is "one hundred fifty-three trillion, one hundred twenty-two billion, three hundred thirteen million, one hundred fifty-three thousand, six hundred forty-two".
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