Base | Representation |
---|---|
bin | 11100100001011000… |
… | …00010001100110101 |
3 | 1110112010220201000020 |
4 | 32100230002030311 |
5 | 222324431124331 |
6 | 11011233035353 |
7 | 1051311643431 |
oct | 162054021465 |
9 | 43463821006 |
10 | 15312364341 |
11 | 6548480a6a |
12 | 2b740b5b59 |
13 | 15a0485921 |
14 | a538d59c1 |
15 | 5e9466c96 |
hex | 390b02335 |
15312364341 has 32 divisors (see below), whose sum is σ = 21299241600. Its totient is φ = 9776517120.
The previous prime is 15312364307. The next prime is 15312364343. The reversal of 15312364341 is 14346321351.
It is a de Polignac number, because none of the positive numbers 2k-15312364341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15312364343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8105125 + ... + 8107013.
It is an arithmetic number, because the mean of its divisors is an integer number (665601300).
Almost surely, 215312364341 is an apocalyptic number.
It is an amenable number.
15312364341 is a deficient number, since it is larger than the sum of its proper divisors (5986877259).
15312364341 is a wasteful number, since it uses less digits than its factorization.
15312364341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3109.
The product of its digits is 25920, while the sum is 33.
Adding to 15312364341 its reverse (14346321351), we get a palindrome (29658685692).
Subtracting from 15312364341 its reverse (14346321351), we obtain a triangular number (966042990 = T43955).
The spelling of 15312364341 in words is "fifteen billion, three hundred twelve million, three hundred sixty-four thousand, three hundred forty-one".
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