Base | Representation |
---|---|
bin | 10110010010000101001… |
… | …001101000001100101111 |
3 | 12102101101220102221012000 |
4 | 112102011021220030233 |
5 | 200041441004013210 |
6 | 3131235403343343 |
7 | 215425416244416 |
oct | 26220511501457 |
9 | 5371356387160 |
10 | 1531242251055 |
11 | 54043a370a90 |
12 | 208921b21b53 |
13 | b151ac771aa |
14 | 54180a8247d |
15 | 29c700a7ac0 |
hex | 1648526832f |
1531242251055 has 32 divisors (see below), whose sum is σ = 2969681944320. Its totient is φ = 742420484640.
The previous prime is 1531242251017. The next prime is 1531242251059. The reversal of 1531242251055 is 5501522421351.
1531242251055 is a `hidden beast` number, since 1 + 5 + 312 + 42 + 251 + 0 + 55 = 666.
It is not a de Polignac number, because 1531242251055 - 218 = 1531241988911 is a prime.
It is a super-2 number, since 2×15312422510552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531242251059) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 515568297 + ... + 515571266.
It is an arithmetic number, because the mean of its divisors is an integer number (92802560760).
Almost surely, 21531242251055 is an apocalyptic number.
1531242251055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1531242251055 is a deficient number, since it is larger than the sum of its proper divisors (1438439693265).
1531242251055 is a wasteful number, since it uses less digits than its factorization.
1531242251055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1031139588 (or 1031139582 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
The spelling of 1531242251055 in words is "one trillion, five hundred thirty-one billion, two hundred forty-two million, two hundred fifty-one thousand, fifty-five".
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