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153126367250113 is a prime number
BaseRepresentation
bin100010110100010010000010…
…101110011100011011000001
3202002011201220211000111111101
4202310102002232130123001
5130032310300004000423
61301401140524214401
744153005062002335
oct4264220256343301
9662151824014441
10153126367250113
1144877589353334
1215210aba69a401
1367599a676499a
1429b54da1457c5
1512a827cb067ad
hex8b4482b9c6c1

153126367250113 has 2 divisors, whose sum is σ = 153126367250114. Its totient is φ = 153126367250112.

The previous prime is 153126367250099. The next prime is 153126367250147. The reversal of 153126367250113 is 311052763621351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152364880642689 + 761486607424 = 12343617^2 + 872632^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-153126367250113 is a prime.

It is not a weakly prime, because it can be changed into another prime (153126367250183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76563183625056 + 76563183625057.

It is an arithmetic number, because the mean of its divisors is an integer number (76563183625057).

Almost surely, 2153126367250113 is an apocalyptic number.

It is an amenable number.

153126367250113 is a deficient number, since it is larger than the sum of its proper divisors (1).

153126367250113 is an equidigital number, since it uses as much as digits as its factorization.

153126367250113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 680400, while the sum is 46.

The spelling of 153126367250113 in words is "one hundred fifty-three trillion, one hundred twenty-six billion, three hundred sixty-seven million, two hundred fifty thousand, one hundred thirteen".