Base | Representation |
---|---|
bin | 100010110100010010000010… |
… | …101110011100011011000001 |
3 | 202002011201220211000111111101 |
4 | 202310102002232130123001 |
5 | 130032310300004000423 |
6 | 1301401140524214401 |
7 | 44153005062002335 |
oct | 4264220256343301 |
9 | 662151824014441 |
10 | 153126367250113 |
11 | 44877589353334 |
12 | 15210aba69a401 |
13 | 67599a676499a |
14 | 29b54da1457c5 |
15 | 12a827cb067ad |
hex | 8b4482b9c6c1 |
153126367250113 has 2 divisors, whose sum is σ = 153126367250114. Its totient is φ = 153126367250112.
The previous prime is 153126367250099. The next prime is 153126367250147. The reversal of 153126367250113 is 311052763621351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152364880642689 + 761486607424 = 12343617^2 + 872632^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153126367250113 is a prime.
It is not a weakly prime, because it can be changed into another prime (153126367250183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76563183625056 + 76563183625057.
It is an arithmetic number, because the mean of its divisors is an integer number (76563183625057).
Almost surely, 2153126367250113 is an apocalyptic number.
It is an amenable number.
153126367250113 is a deficient number, since it is larger than the sum of its proper divisors (1).
153126367250113 is an equidigital number, since it uses as much as digits as its factorization.
153126367250113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 46.
The spelling of 153126367250113 in words is "one hundred fifty-three trillion, one hundred twenty-six billion, three hundred sixty-seven million, two hundred fifty thousand, one hundred thirteen".
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