Base | Representation |
---|---|
bin | 10110010010001010011… |
… | …100011000011011000101 |
3 | 12102101122002112112220022 |
4 | 112102022130120123011 |
5 | 200042131222201003 |
6 | 3131252254544525 |
7 | 215430545121101 |
oct | 26221234303305 |
9 | 5371562475808 |
10 | 1531331053253 |
11 | 540485504431 |
12 | 208947808145 |
13 | b1533499b81 |
14 | 5418c79a901 |
15 | 29c77c99738 |
hex | 1648a7186c5 |
1531331053253 has 4 divisors (see below), whose sum is σ = 1597910664288. Its totient is φ = 1464751442220.
The previous prime is 1531331053247. The next prime is 1531331053309. The reversal of 1531331053253 is 3523501331351.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1531331053253 - 214 = 1531331036869 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1531331053753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33289805483 + ... + 33289805528.
It is an arithmetic number, because the mean of its divisors is an integer number (399477666072).
Almost surely, 21531331053253 is an apocalyptic number.
It is an amenable number.
1531331053253 is a deficient number, since it is larger than the sum of its proper divisors (66579611035).
1531331053253 is an equidigital number, since it uses as much as digits as its factorization.
1531331053253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66579611034.
The product of its (nonzero) digits is 60750, while the sum is 35.
The spelling of 1531331053253 in words is "one trillion, five hundred thirty-one billion, three hundred thirty-one million, fifty-three thousand, two hundred fifty-three".
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