Base | Representation |
---|---|
bin | 10110010010001010011… |
… | …100011000011010111111 |
3 | 12102101122002112112220002 |
4 | 112102022130120122333 |
5 | 200042131222200442 |
6 | 3131252254544515 |
7 | 215430545121062 |
oct | 26221234303277 |
9 | 5371562475802 |
10 | 1531331053247 |
11 | 540485504426 |
12 | 20894780813b |
13 | b1533499b78 |
14 | 5418c79a8d9 |
15 | 29c77c99732 |
hex | 1648a7186bf |
1531331053247 has 2 divisors, whose sum is σ = 1531331053248. Its totient is φ = 1531331053246.
The previous prime is 1531331053229. The next prime is 1531331053309. The reversal of 1531331053247 is 7423501331351.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1531331053247 - 214 = 1531331036863 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1531331053247.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1531331056247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765665526623 + 765665526624.
It is an arithmetic number, because the mean of its divisors is an integer number (765665526624).
Almost surely, 21531331053247 is an apocalyptic number.
1531331053247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1531331053247 is an equidigital number, since it uses as much as digits as its factorization.
1531331053247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 38.
Adding to 1531331053247 its reverse (7423501331351), we get a palindrome (8954832384598).
The spelling of 1531331053247 in words is "one trillion, five hundred thirty-one billion, three hundred thirty-one million, fifty-three thousand, two hundred forty-seven".
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