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1531401413407 = 3929338973899
BaseRepresentation
bin10110010010001110101…
…000110010001100011111
312102101210222221012212221
4112102032220302030133
5200042302230212112
63131303251010211
7215432361144535
oct26221650621437
95371728835787
101531401413407
115405111a1018
12208967299967
13b1544c335b8
1454197c74155
1529c7e046e07
hex1648ea3231f

1531401413407 has 4 divisors (see below), whose sum is σ = 1531440426600. Its totient is φ = 1531362400216.

The previous prime is 1531401413293. The next prime is 1531401413413. The reversal of 1531401413407 is 7043141041351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1531401413407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1531401416407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19447657 + ... + 19526242.

It is an arithmetic number, because the mean of its divisors is an integer number (382860106650).

Almost surely, 21531401413407 is an apocalyptic number.

1531401413407 is a deficient number, since it is larger than the sum of its proper divisors (39013193).

1531401413407 is an equidigital number, since it uses as much as digits as its factorization.

1531401413407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39013192.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 1531401413407 its reverse (7043141041351), we get a palindrome (8574542454758).

The spelling of 1531401413407 in words is "one trillion, five hundred thirty-one billion, four hundred one million, four hundred thirteen thousand, four hundred seven".

Divisors: 1 39293 38973899 1531401413407