15314211241351 has 4 divisors (see below), whose sum is σ = 16706412263304. Its totient is φ = 13922010219400.

The previous prime is 15314211241337. The next prime is 15314211241363.

15314211241351 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15314211241351 - 2¹³ = 15314211233159 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15314211241331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 696100510960 + ... + 696100510981.

It is an arithmetic number, because the mean of its divisors is an integer number (4176603065826).

Almost surely, 2^{15314211241351} is an apocalyptic number.

15314211241351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

15314211241351 is a deficient number, since it is larger than the sum of its proper divisors (1392201021953).

15314211241351 is a wasteful number, since it uses less digits than its factorization.

15314211241351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1392201021952.

The product of its digits is 14400, while the sum is 34.

It can be divided in two parts, 1531421 and 1241351, that added together give a palindrome (2772772).

The spelling of 15314211241351 in words is "fifteen trillion, three hundred fourteen billion, two hundred eleven million, two hundred forty-one thousand, three hundred fifty-one".