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153150135015433 is a prime number
BaseRepresentation
bin100010110100101000001011…
…011001010001100000001001
3202002021000021020021002002211
4202310220023121101200021
5130033202434030443213
61301420111210025121
744154506054451643
oct4264501331214011
9662230236232084
10153150135015433
1144886675667196
12152156324181a1
13675bcc38cb84a
1429b67129ab893
1512a8bbe52253d
hex8b4a0b651809

153150135015433 has 2 divisors, whose sum is σ = 153150135015434. Its totient is φ = 153150135015432.

The previous prime is 153150135015419. The next prime is 153150135015461. The reversal of 153150135015433 is 334510531051351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117288098581369 + 35862036434064 = 10829963^2 + 5988492^2 .

It is a cyclic number.

It is not a de Polignac number, because 153150135015433 - 233 = 153141545080841 is a prime.

It is not a weakly prime, because it can be changed into another prime (153150135015733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76575067507716 + 76575067507717.

It is an arithmetic number, because the mean of its divisors is an integer number (76575067507717).

Almost surely, 2153150135015433 is an apocalyptic number.

It is an amenable number.

153150135015433 is a deficient number, since it is larger than the sum of its proper divisors (1).

153150135015433 is an equidigital number, since it uses as much as digits as its factorization.

153150135015433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 202500, while the sum is 40.

Adding to 153150135015433 its reverse (334510531051351), we get a palindrome (487660666066784).

The spelling of 153150135015433 in words is "one hundred fifty-three trillion, one hundred fifty billion, one hundred thirty-five million, fifteen thousand, four hundred thirty-three".