Base | Representation |
---|---|
bin | 11100100001101111… |
… | …11000010000000001 |
3 | 1110112100202110020012 |
4 | 32100313320100001 |
5 | 222331230004223 |
6 | 11011423354305 |
7 | 1051350225014 |
oct | 162067702001 |
9 | 43470673205 |
10 | 15315469313 |
11 | 654a201861 |
12 | 2b75152995 |
13 | 15a1001ca1 |
14 | a540a337b |
15 | 5e987bc78 |
hex | 390df8401 |
15315469313 has 2 divisors, whose sum is σ = 15315469314. Its totient is φ = 15315469312.
The previous prime is 15315469291. The next prime is 15315469321. The reversal of 15315469313 is 31396451351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11149670464 + 4165798849 = 105592^2 + 64543^2 .
It is an emirp because it is prime and its reverse (31396451351) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15315469313 is a prime.
It is not a weakly prime, because it can be changed into another prime (15315469363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7657734656 + 7657734657.
It is an arithmetic number, because the mean of its divisors is an integer number (7657734657).
Almost surely, 215315469313 is an apocalyptic number.
It is an amenable number.
15315469313 is a deficient number, since it is larger than the sum of its proper divisors (1).
15315469313 is an equidigital number, since it uses as much as digits as its factorization.
15315469313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 145800, while the sum is 41.
The spelling of 15315469313 in words is "fifteen billion, three hundred fifteen million, four hundred sixty-nine thousand, three hundred thirteen".
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