Base | Representation |
---|---|
bin | 10110010010101110110… |
… | …101000110101100111011 |
3 | 12102110012122020011200012 |
4 | 112102232311012230323 |
5 | 200044404011422133 |
6 | 3131433023132135 |
7 | 215451640006133 |
oct | 26225665065473 |
9 | 5373178204605 |
10 | 1531941514043 |
11 | 540769057686 |
12 | 208a9814404b |
13 | b15ccab8c85 |
14 | 542098a7ac3 |
15 | 29cb1681b48 |
hex | 164aed46b3b |
1531941514043 has 2 divisors, whose sum is σ = 1531941514044. Its totient is φ = 1531941514042.
The previous prime is 1531941514007. The next prime is 1531941514067. The reversal of 1531941514043 is 3404151491351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1531941514043 - 212 = 1531941509947 is a prime.
It is not a weakly prime, because it can be changed into another prime (1531941514073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765970757021 + 765970757022.
It is an arithmetic number, because the mean of its divisors is an integer number (765970757022).
Almost surely, 21531941514043 is an apocalyptic number.
1531941514043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1531941514043 is an equidigital number, since it uses as much as digits as its factorization.
1531941514043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 1531941514043 in words is "one trillion, five hundred thirty-one billion, nine hundred forty-one million, five hundred fourteen thousand, forty-three".
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