Base | Representation |
---|---|
bin | 10110010010111000010… |
… | …000100101010001010011 |
3 | 12102110121122220110120212 |
4 | 112102320100211101103 |
5 | 200100220011241313 |
6 | 3131500433554335 |
7 | 215455600451663 |
oct | 26227020452123 |
9 | 5373548813525 |
10 | 1532099712083 |
11 | 54083a389166 |
12 | 208b211159ab |
13 | b16267c8495 |
14 | 542228c81a3 |
15 | 29cc04d03a8 |
hex | 164b8425453 |
1532099712083 has 2 divisors, whose sum is σ = 1532099712084. Its totient is φ = 1532099712082.
The previous prime is 1532099711999. The next prime is 1532099712089. The reversal of 1532099712083 is 3802179902351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1532099712083 - 216 = 1532099646547 is a prime.
It is a super-2 number, since 2×15320997120832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1532099712089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766049856041 + 766049856042.
It is an arithmetic number, because the mean of its divisors is an integer number (766049856042).
Almost surely, 21532099712083 is an apocalyptic number.
1532099712083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1532099712083 is an equidigital number, since it uses as much as digits as its factorization.
1532099712083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 816480, while the sum is 50.
The spelling of 1532099712083 in words is "one trillion, five hundred thirty-two billion, ninety-nine million, seven hundred twelve thousand, eighty-three".
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