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153230114142121 is a prime number
BaseRepresentation
bin100010110101110010101010…
…100001011011011110101001
3202002112122201010002200022011
4202311302222201123132221
5130041010233210021441
61301520535340155521
744163340034016262
oct4265625241333651
9662478633080264
10153230114142121
11449075878068a5
1215229033238ba1
1367666cb605893
1429ba53ca71969
1512aad00c6b581
hex8b5caa85b7a9

153230114142121 has 2 divisors, whose sum is σ = 153230114142122. Its totient is φ = 153230114142120.

The previous prime is 153230114142059. The next prime is 153230114142151. The reversal of 153230114142121 is 121241411032351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89824901760000 + 63405212382121 = 9477600^2 + 7962739^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-153230114142121 is a prime.

It is not a weakly prime, because it can be changed into another prime (153230114142151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76615057071060 + 76615057071061.

It is an arithmetic number, because the mean of its divisors is an integer number (76615057071061).

Almost surely, 2153230114142121 is an apocalyptic number.

It is an amenable number.

153230114142121 is a deficient number, since it is larger than the sum of its proper divisors (1).

153230114142121 is an equidigital number, since it uses as much as digits as its factorization.

153230114142121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 153230114142121 its reverse (121241411032351), we get a palindrome (274471525174472).

The spelling of 153230114142121 in words is "one hundred fifty-three trillion, two hundred thirty billion, one hundred fourteen million, one hundred forty-two thousand, one hundred twenty-one".