Base | Representation |
---|---|
bin | 10110010011000101011… |
… | …100110001100110100110 |
3 | 12102111012002022200012001 |
4 | 112103011130301212212 |
5 | 200101143134342014 |
6 | 3131534421115514 |
7 | 215464225461433 |
oct | 26230534614646 |
9 | 5374162280161 |
10 | 1532321012134 |
11 | 54094329a170 |
12 | 208b83258b9a |
13 | b16605cc863 |
14 | 54244052b8a |
15 | 29cd4b45974 |
hex | 164c57319a6 |
1532321012134 has 8 divisors (see below), whose sum is σ = 2507434383528. Its totient is φ = 696509550960.
The previous prime is 1532321012119. The next prime is 1532321012191. The reversal of 1532321012134 is 4312101232351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34825477527 + ... + 34825477570.
It is an arithmetic number, because the mean of its divisors is an integer number (313429297941).
Almost surely, 21532321012134 is an apocalyptic number.
1532321012134 is a deficient number, since it is larger than the sum of its proper divisors (975113371394).
1532321012134 is a wasteful number, since it uses less digits than its factorization.
1532321012134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69650955110.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1532321012134 its reverse (4312101232351), we get a palindrome (5844422244485).
The spelling of 1532321012134 in words is "one trillion, five hundred thirty-two billion, three hundred twenty-one million, twelve thousand, one hundred thirty-four".
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