Base | Representation |
---|---|
bin | 1000111011000101101… |
… | …0011100011111000101 |
3 | 112122200202122220211102 |
4 | 2032301122130133011 |
5 | 10002424342330023 |
6 | 154231502345445 |
7 | 14034632342351 |
oct | 2166132343705 |
9 | 478622586742 |
10 | 153300355013 |
11 | 5a018065783 |
12 | 25863b8b285 |
13 | 115c1257250 |
14 | 75c3c20461 |
15 | 3ec3702628 |
hex | 23b169c7c5 |
153300355013 has 16 divisors (see below), whose sum is σ = 165763992576. Its totient is φ = 140933658240.
The previous prime is 153300354979. The next prime is 153300355121. The reversal of 153300355013 is 310553003351.
It is a cyclic number.
It is not a de Polignac number, because 153300355013 - 210 = 153300353989 is a prime.
It is a super-2 number, since 2×1533003550132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153300355213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3609620 + ... + 3651842.
It is an arithmetic number, because the mean of its divisors is an integer number (10360249536).
Almost surely, 2153300355013 is an apocalyptic number.
153300355013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
153300355013 is a deficient number, since it is larger than the sum of its proper divisors (12463637563).
153300355013 is a wasteful number, since it uses less digits than its factorization.
153300355013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43364.
The product of its (nonzero) digits is 10125, while the sum is 29.
Adding to 153300355013 its reverse (310553003351), we get a palindrome (463853358364).
The spelling of 153300355013 in words is "one hundred fifty-three billion, three hundred million, three hundred fifty-five thousand, thirteen".
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