Base | Representation |
---|---|
bin | 100010110110110101010000… |
… | …110100100011011100000011 |
3 | 202002210111021201212001202212 |
4 | 202312311100310203130003 |
5 | 130043143211123300201 |
6 | 1302013443233132335 |
7 | 44201451100553552 |
oct | 4266652064433403 |
9 | 662714251761685 |
10 | 153301623650051 |
11 | 44934942a92588 |
12 | 1523aa6b6ba0ab |
13 | 67703866c1096 |
14 | 29bdba3d43d99 |
15 | 12acad8b53abb |
hex | 8b6d50d23703 |
153301623650051 has 2 divisors, whose sum is σ = 153301623650052. Its totient is φ = 153301623650050.
The previous prime is 153301623650017. The next prime is 153301623650057. The reversal of 153301623650051 is 150056326103351.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153301623650051 is a prime.
It is a super-2 number, since 2×1533016236500512 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 153301623649990 and 153301623650008.
It is not a weakly prime, because it can be changed into another prime (153301623650057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76650811825025 + 76650811825026.
It is an arithmetic number, because the mean of its divisors is an integer number (76650811825026).
Almost surely, 2153301623650051 is an apocalyptic number.
153301623650051 is a deficient number, since it is larger than the sum of its proper divisors (1).
153301623650051 is an equidigital number, since it uses as much as digits as its factorization.
153301623650051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 153301623650051 in words is "one hundred fifty-three trillion, three hundred one billion, six hundred twenty-three million, six hundred fifty thousand, fifty-one".
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