Base | Representation |
---|---|
bin | 10110010011110110011… |
… | …001000111001000100011 |
3 | 12102120022022102001110022 |
4 | 112103312121013020203 |
5 | 200104333341312311 |
6 | 3132152112424055 |
7 | 215523456062552 |
oct | 26236631071043 |
9 | 5376268361408 |
10 | 1533142135331 |
11 | 541224848184 |
12 | 20917224802b |
13 | b176176a181 |
14 | 542c1119d99 |
15 | 29d31c915db |
hex | 164f6647223 |
1533142135331 has 2 divisors, whose sum is σ = 1533142135332. Its totient is φ = 1533142135330.
The previous prime is 1533142135321. The next prime is 1533142135337. The reversal of 1533142135331 is 1335312413351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1533142135331 - 218 = 1533141873187 is a prime.
It is a super-2 number, since 2×15331421353312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1533142135291 and 1533142135300.
It is not a weakly prime, because it can be changed into another prime (1533142135337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766571067665 + 766571067666.
It is an arithmetic number, because the mean of its divisors is an integer number (766571067666).
Almost surely, 21533142135331 is an apocalyptic number.
1533142135331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1533142135331 is an equidigital number, since it uses as much as digits as its factorization.
1533142135331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48600, while the sum is 35.
Adding to 1533142135331 its reverse (1335312413351), we get a palindrome (2868454548682).
The spelling of 1533142135331 in words is "one trillion, five hundred thirty-three billion, one hundred forty-two million, one hundred thirty-five thousand, three hundred thirty-one".
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