Base | Representation |
---|---|
bin | 1000111011011101101… |
… | …0110110010100000111 |
3 | 112122221210021112000221 |
4 | 2032313122312110013 |
5 | 10003131141432403 |
6 | 154245502245211 |
7 | 14040265016653 |
oct | 2166732662407 |
9 | 478853245027 |
10 | 153401124103 |
11 | 5a069a32017 |
12 | 25891886807 |
13 | 116090a9b26 |
14 | 75d3371a63 |
15 | 3ecc4a9dbd |
hex | 23b76b6507 |
153401124103 has 4 divisors (see below), whose sum is σ = 153403684648. Its totient is φ = 153398563560.
The previous prime is 153401124089. The next prime is 153401124113. The reversal of 153401124103 is 301421104351.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301421104351 = 67 ⋅4498822453.
It is a cyclic number.
It is not a de Polignac number, because 153401124103 - 233 = 144811189511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153401124113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1188201 + ... + 1310962.
It is an arithmetic number, because the mean of its divisors is an integer number (38350921162).
Almost surely, 2153401124103 is an apocalyptic number.
153401124103 is a deficient number, since it is larger than the sum of its proper divisors (2560545).
153401124103 is an equidigital number, since it uses as much as digits as its factorization.
153401124103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2560544.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 153401124103 its reverse (301421104351), we get a palindrome (454822228454).
The spelling of 153401124103 in words is "one hundred fifty-three billion, four hundred one million, one hundred twenty-four thousand, one hundred three".
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