Base | Representation |
---|---|
bin | 100010111000010011000010… |
… | …111010110001110001001101 |
3 | 202010011010012120210222012001 |
4 | 202320103002322301301031 |
5 | 130101320423431211140 |
6 | 1302132015351112301 |
7 | 44211644355541660 |
oct | 4270230272616115 |
9 | 663133176728161 |
10 | 153402322132045 |
11 | 44973617720528 |
12 | 15256493372691 |
13 | 6779a13b2ac7c |
14 | 29c49d7a656d7 |
15 | 12b052e360e9a |
hex | 8b84c2eb1c4d |
153402322132045 has 32 divisors (see below), whose sum is σ = 212529078685440. Its totient is φ = 104117775943680.
The previous prime is 153402322132013. The next prime is 153402322132051. The reversal of 153402322132045 is 540231223204351.
It is not a de Polignac number, because 153402322132045 - 25 = 153402322132013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153402322131995 and 153402322132013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17001252 + ... + 24409981.
It is an arithmetic number, because the mean of its divisors is an integer number (6641533708920).
Almost surely, 2153402322132045 is an apocalyptic number.
It is an amenable number.
153402322132045 is a deficient number, since it is larger than the sum of its proper divisors (59126756553395).
153402322132045 is a wasteful number, since it uses less digits than its factorization.
153402322132045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41412325.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 153402322132045 its reverse (540231223204351), we get a palindrome (693633545336396).
The spelling of 153402322132045 in words is "one hundred fifty-three trillion, four hundred two billion, three hundred twenty-two million, one hundred thirty-two thousand, forty-five".
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