Base | Representation |
---|---|
bin | 11100100100111010… |
… | …01000101001110010 |
3 | 1110121012201000101021 |
4 | 32102131020221302 |
5 | 222410023404132 |
6 | 11014212330054 |
7 | 1052121646666 |
oct | 162235105162 |
9 | 43535630337 |
10 | 15342013042 |
11 | 6563191524 |
12 | 2b8201392a |
13 | 15a6666a35 |
14 | a578128a6 |
15 | 5ebd71997 |
hex | 392748a72 |
15342013042 has 4 divisors (see below), whose sum is σ = 23013019566. Its totient is φ = 7671006520.
The previous prime is 15342013031. The next prime is 15342013079. The reversal of 15342013042 is 24031024351.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 14908165801 + 433847241 = 122099^2 + 20829^2 .
It is a junction number, because it is equal to n+sod(n) for n = 15342012998 and 15342013016.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3835503259 + ... + 3835503262.
Almost surely, 215342013042 is an apocalyptic number.
15342013042 is a deficient number, since it is larger than the sum of its proper divisors (7671006524).
15342013042 is an equidigital number, since it uses as much as digits as its factorization.
15342013042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7671006523.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 15342013042 its reverse (24031024351), we get a palindrome (39373037393).
The spelling of 15342013042 in words is "fifteen billion, three hundred forty-two million, thirteen thousand, forty-two".
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