Base | Representation |
---|---|
bin | 1101111101000011011011… |
… | …0001111110100001001111 |
3 | 2000022201210011000201202202 |
4 | 3133100312301332201033 |
5 | 4002333011304031421 |
6 | 52344133330512115 |
7 | 3142314333246464 |
oct | 337206661764117 |
9 | 60281704021682 |
10 | 15342542252111 |
11 | 4985810138518 |
12 | 18795a243563b |
13 | 873a45a04a19 |
14 | 3b0823ab366b |
15 | 1b9164ad010b |
hex | df436c7e84f |
15342542252111 has 4 divisors (see below), whose sum is σ = 15342562363824. Its totient is φ = 15342522140400.
The previous prime is 15342542252101. The next prime is 15342542252113. The reversal of 15342542252111 is 11125224524351.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15342542252111 is a prime.
It is a super-2 number, since 2×153425422521112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15342542252113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8864510 + ... + 10452971.
It is an arithmetic number, because the mean of its divisors is an integer number (3835640590956).
Almost surely, 215342542252111 is an apocalyptic number.
15342542252111 is a deficient number, since it is larger than the sum of its proper divisors (20111713).
15342542252111 is an equidigital number, since it uses as much as digits as its factorization.
15342542252111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20111712.
The product of its digits is 96000, while the sum is 38.
Adding to 15342542252111 its reverse (11125224524351), we get a palindrome (26467766776462).
The spelling of 15342542252111 in words is "fifteen trillion, three hundred forty-two billion, five hundred forty-two million, two hundred fifty-two thousand, one hundred eleven".
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