Base | Representation |
---|---|
bin | 10110010100111001000… |
… | …111101110101010010001 |
3 | 12102200012022222101202211 |
4 | 112110321013232222101 |
5 | 200114131440331423 |
6 | 3132455143512121 |
7 | 215563301603101 |
oct | 26247107565221 |
9 | 5380168871684 |
10 | 1534261652113 |
11 | 541749782763 |
12 | 209425158641 |
13 | b18ac692338 |
14 | 54389a99201 |
15 | 29d9a1d010d |
hex | 165391eea91 |
1534261652113 has 2 divisors, whose sum is σ = 1534261652114. Its totient is φ = 1534261652112.
The previous prime is 1534261652107. The next prime is 1534261652117. The reversal of 1534261652113 is 3112561624351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1533850049169 + 411602944 = 1238487^2 + 20288^2 .
It is a cyclic number.
It is not a de Polignac number, because 1534261652113 - 217 = 1534261521041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1534261652117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767130826056 + 767130826057.
It is an arithmetic number, because the mean of its divisors is an integer number (767130826057).
Almost surely, 21534261652113 is an apocalyptic number.
It is an amenable number.
1534261652113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1534261652113 is an equidigital number, since it uses as much as digits as its factorization.
1534261652113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129600, while the sum is 40.
The spelling of 1534261652113 in words is "one trillion, five hundred thirty-four billion, two hundred sixty-one million, six hundred fifty-two thousand, one hundred thirteen".
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