Base | Representation |
---|---|
bin | 100010111000101101111101… |
… | …000010111000100110011111 |
3 | 202010020212210011010120221122 |
4 | 202320231331002320212133 |
5 | 130102304111420420020 |
6 | 1302153154341321155 |
7 | 44214016346631611 |
oct | 4270557502704637 |
9 | 663225704116848 |
10 | 153431214623135 |
11 | 449848a3790739 |
12 | 1525bbb74061bb |
13 | 677c669913647 |
14 | 29c6178d78db1 |
15 | 12b1170b1e125 |
hex | 8b8b7d0b899f |
153431214623135 has 16 divisors (see below), whose sum is σ = 187592008695840. Its totient is φ = 120428619991680.
The previous prime is 153431214623111. The next prime is 153431214623149. The reversal of 153431214623135 is 531326412134351.
It is not a de Polignac number, because 153431214623135 - 210 = 153431214622111 is a prime.
It is a super-2 number, since 2×1534312146231352 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94804025 + ... + 96408845.
It is an arithmetic number, because the mean of its divisors is an integer number (11724500543490).
Almost surely, 2153431214623135 is an apocalyptic number.
153431214623135 is a deficient number, since it is larger than the sum of its proper divisors (34160794072705).
153431214623135 is a wasteful number, since it uses less digits than its factorization.
153431214623135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1965658.
The product of its digits is 777600, while the sum is 44.
Adding to 153431214623135 its reverse (531326412134351), we get a palindrome (684757626757486).
The spelling of 153431214623135 in words is "one hundred fifty-three trillion, four hundred thirty-one billion, two hundred fourteen million, six hundred twenty-three thousand, one hundred thirty-five".
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