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15345005315131 is a prime number
BaseRepresentation
bin1101111101001100100110…
…0101110100010000111011
32000022222010210201022001001
43133103021211310100323
54002403032330041011
652345221554505431
73142432352035312
oct337231145642073
960288123638031
1015345005315131
114986864503198
121879b6b295277
138740490a086b
143b09b8c6b279
151b925ae617c1
hexdf4c997443b

15345005315131 has 2 divisors, whose sum is σ = 15345005315132. Its totient is φ = 15345005315130.

The previous prime is 15345005315119. The next prime is 15345005315141. The reversal of 15345005315131 is 13151350054351.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15345005315131 - 25 = 15345005315099 is a prime.

It is a super-2 number, since 2×153450053151312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15345005315141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7672502657565 + 7672502657566.

It is an arithmetic number, because the mean of its divisors is an integer number (7672502657566).

Almost surely, 215345005315131 is an apocalyptic number.

15345005315131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15345005315131 is an equidigital number, since it uses as much as digits as its factorization.

15345005315131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67500, while the sum is 37.

Adding to 15345005315131 its reverse (13151350054351), we get a palindrome (28496355369482).

The spelling of 15345005315131 in words is "fifteen trillion, three hundred forty-five billion, five million, three hundred fifteen thousand, one hundred thirty-one".