Base | Representation |
---|---|
bin | 1000111011101001011… |
… | …0001100011001101101 |
3 | 112200002012200122012121 |
4 | 2032322112030121231 |
5 | 10003231230014001 |
6 | 154254415032541 |
7 | 14041432323613 |
oct | 2167226143155 |
9 | 480065618177 |
10 | 153450235501 |
11 | 5a094726152 |
12 | 258a620b751 |
13 | 11616313924 |
14 | 75d9ab76b3 |
15 | 3ed195b6a1 |
hex | 23ba58c66d |
153450235501 has 4 divisors (see below), whose sum is σ = 153816465600. Its totient is φ = 153084005404.
The previous prime is 153450235483. The next prime is 153450235567. The reversal of 153450235501 is 105532054351.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 153450235501 - 213 = 153450227309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153450235801) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183114421 + ... + 183115258.
It is an arithmetic number, because the mean of its divisors is an integer number (38454116400).
Almost surely, 2153450235501 is an apocalyptic number.
It is an amenable number.
153450235501 is a deficient number, since it is larger than the sum of its proper divisors (366230099).
153450235501 is an equidigital number, since it uses as much as digits as its factorization.
153450235501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 366230098.
The product of its (nonzero) digits is 45000, while the sum is 34.
Adding to 153450235501 its reverse (105532054351), we get a palindrome (258982289852).
The spelling of 153450235501 in words is "one hundred fifty-three billion, four hundred fifty million, two hundred thirty-five thousand, five hundred one".
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