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1535001130121 is a prime number
BaseRepresentation
bin10110010101100101001…
…100100111010010001001
312102202002212102202220012
4112111211030213102021
5200122140242130441
63133100401241305
7215620521216464
oct26254514472211
95382085382805
101535001130121
11541a99136508
122095b0933235
13b19999447a4
1454419d8c2db
1529de009e9eb
hex16565327489

1535001130121 has 2 divisors, whose sum is σ = 1535001130122. Its totient is φ = 1535001130120.

The previous prime is 1535001130099. The next prime is 1535001130141. The reversal of 1535001130121 is 1210311005351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1455736358521 + 79264771600 = 1206539^2 + 281540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1535001130121 is a prime.

It is not a weakly prime, because it can be changed into another prime (1535001130141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767500565060 + 767500565061.

It is an arithmetic number, because the mean of its divisors is an integer number (767500565061).

Almost surely, 21535001130121 is an apocalyptic number.

It is an amenable number.

1535001130121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1535001130121 is an equidigital number, since it uses as much as digits as its factorization.

1535001130121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 1535001130121 its reverse (1210311005351), we get a palindrome (2745312135472).

The spelling of 1535001130121 in words is "one trillion, five hundred thirty-five billion, one million, one hundred thirty thousand, one hundred twenty-one".