Base | Representation |
---|---|
bin | 100010111101001011101110… |
… | …111011111001001110100111 |
3 | 202011100012211022000212012120 |
4 | 202331023232323321032213 |
5 | 130122321030411240320 |
6 | 1302550143215521023 |
7 | 44245131434124636 |
oct | 4275135673711647 |
9 | 664305738025176 |
10 | 153738068071335 |
11 | 44a92a48535010 |
12 | 152ab573b29173 |
13 | 67a258c585937 |
14 | 29d6d683a951d |
15 | 12b912ece9440 |
hex | 8bd2eeef93a7 |
153738068071335 has 48 divisors (see below), whose sum is σ = 277915086184320. Its totient is φ = 71969335876480.
The previous prime is 153738068071333. The next prime is 153738068071373. The reversal of 153738068071335 is 533170860837351.
It is not a de Polignac number, because 153738068071335 - 21 = 153738068071333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153738068071333) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 553812405 + ... + 554089934.
It is an arithmetic number, because the mean of its divisors is an integer number (5789897628840).
Almost surely, 2153738068071335 is an apocalyptic number.
153738068071335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153738068071335 is a deficient number, since it is larger than the sum of its proper divisors (124177018112985).
153738068071335 is a wasteful number, since it uses less digits than its factorization.
153738068071335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1107902416 (or 1107902387 counting only the distinct ones).
The product of its (nonzero) digits is 38102400, while the sum is 60.
The spelling of 153738068071335 in words is "one hundred fifty-three trillion, seven hundred thirty-eight billion, sixty-eight million, seventy-one thousand, three hundred thirty-five".
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