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15380137 is a prime number
BaseRepresentation
bin111010101010…
…111010101001
31001221101120201
4322222322221
512414131022
61305352201
7244505023
oct72527251
931841521
1015380137
118755363
125198661
133256696
142085013
15153c127
hexeaaea9

15380137 has 2 divisors, whose sum is σ = 15380138. Its totient is φ = 15380136.

The previous prime is 15380119. The next prime is 15380143. The reversal of 15380137 is 73108351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15280281 + 99856 = 3909^2 + 316^2 .

It is an emirp because it is prime and its reverse (73108351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15380137 - 219 = 14855849 is a prime.

It is a super-2 number, since 2×153801372 = 473097228277538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15380107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7690068 + 7690069.

It is an arithmetic number, because the mean of its divisors is an integer number (7690069).

Almost surely, 215380137 is an apocalyptic number.

It is an amenable number.

15380137 is a deficient number, since it is larger than the sum of its proper divisors (1).

15380137 is an equidigital number, since it uses as much as digits as its factorization.

15380137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 28.

The square root of 15380137 is about 3921.7517769487. The cubic root of 15380137 is about 248.6871821040.

Adding to 15380137 its reverse (73108351), we get a palindrome (88488488).

The spelling of 15380137 in words is "fifteen million, three hundred eighty thousand, one hundred thirty-seven".