Base | Representation |
---|---|
bin | 10110011000110011100… |
… | …010111001001100001011 |
3 | 12110002001010200220101211 |
4 | 112120303202321030023 |
5 | 200201233021432011 |
6 | 3134432110553551 |
7 | 216102356250451 |
oct | 26306342711413 |
9 | 5402033626354 |
10 | 1538463077131 |
11 | 543505332542 |
12 | 20a1b82088b7 |
13 | b20cbc49846 |
14 | 54667a829d1 |
15 | 2a043e91b21 |
hex | 166338b930b |
1538463077131 has 2 divisors, whose sum is σ = 1538463077132. Its totient is φ = 1538463077130.
The previous prime is 1538463077051. The next prime is 1538463077141. The reversal of 1538463077131 is 1317703648351.
It is a strong prime.
It is an emirp because it is prime and its reverse (1317703648351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1538463077131 - 213 = 1538463068939 is a prime.
It is a super-2 number, since 2×15384630771312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1538463077141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 769231538565 + 769231538566.
It is an arithmetic number, because the mean of its divisors is an integer number (769231538566).
Almost surely, 21538463077131 is an apocalyptic number.
1538463077131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1538463077131 is an equidigital number, since it uses as much as digits as its factorization.
1538463077131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1270080, while the sum is 49.
The spelling of 1538463077131 in words is "one trillion, five hundred thirty-eight billion, four hundred sixty-three million, seventy-seven thousand, one hundred thirty-one".
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