Base | Representation |
---|---|
bin | 11100101011110101… |
… | …10000011110110001 |
3 | 1110202021000122102111 |
4 | 32111322300132301 |
5 | 223014412010001 |
6 | 11024045445321 |
7 | 1053425526613 |
oct | 162572603661 |
9 | 43667018374 |
10 | 15400110001 |
11 | 6592a62641 |
12 | 2b99570841 |
13 | 15b56c8733 |
14 | a61416db3 |
15 | 601eea851 |
hex | 395eb07b1 |
15400110001 has 2 divisors, whose sum is σ = 15400110002. Its totient is φ = 15400110000.
The previous prime is 15400109983. The next prime is 15400110013. The reversal of 15400110001 is 10001100451.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10136462400 + 5263647601 = 100680^2 + 72551^2 .
It is an emirp because it is prime and its reverse (10001100451) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15400110001 - 25 = 15400109969 is a prime.
It is not a weakly prime, because it can be changed into another prime (15400110031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7700055000 + 7700055001.
It is an arithmetic number, because the mean of its divisors is an integer number (7700055001).
Almost surely, 215400110001 is an apocalyptic number.
It is an amenable number.
15400110001 is a deficient number, since it is larger than the sum of its proper divisors (1).
15400110001 is an equidigital number, since it uses as much as digits as its factorization.
15400110001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 15400110001 its reverse (10001100451), we get a palindrome (25401210452).
The spelling of 15400110001 in words is "fifteen billion, four hundred million, one hundred ten thousand, one".
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