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154013103121313 is a prime number
BaseRepresentation
bin100011000001001011111000…
…010011010110001110100001
3202012022111201222000000200002
4203001023320103112032201
5130141322313344340223
61303320350503305345
744304036161356412
oct4301137023261641
9665274658000602
10154013103121313
1145089654664907
121533493074b255
1367c24b1200767
142a063b9a89809
1512c137a90ae28
hex8c12f84d63a1

154013103121313 has 2 divisors, whose sum is σ = 154013103121314. Its totient is φ = 154013103121312.

The previous prime is 154013103121291. The next prime is 154013103121447. The reversal of 154013103121313 is 313121301310451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109490419830289 + 44522683291024 = 10463767^2 + 6672532^2 .

It is a cyclic number.

It is not a de Polignac number, because 154013103121313 - 232 = 154008808154017 is a prime.

It is not a weakly prime, because it can be changed into another prime (154013103171313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77006551560656 + 77006551560657.

It is an arithmetic number, because the mean of its divisors is an integer number (77006551560657).

Almost surely, 2154013103121313 is an apocalyptic number.

It is an amenable number.

154013103121313 is a deficient number, since it is larger than the sum of its proper divisors (1).

154013103121313 is an equidigital number, since it uses as much as digits as its factorization.

154013103121313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 29.

Adding to 154013103121313 its reverse (313121301310451), we get a palindrome (467134404431764).

The spelling of 154013103121313 in words is "one hundred fifty-four trillion, thirteen billion, one hundred three million, one hundred twenty-one thousand, three hundred thirteen".