Base | Representation |
---|---|
bin | 1110000000100011001111… |
… | …1111111011111101011011 |
3 | 2000112110212102112202211021 |
4 | 3200020303333323331123 |
5 | 4004324034012402024 |
6 | 52431511315143311 |
7 | 3146542260232663 |
oct | 340106377737533 |
9 | 60473772482737 |
10 | 15402625122139 |
11 | 49a9242377002 |
12 | 188916bba4b37 |
13 | 8795cc688718 |
14 | 3b36c35791a3 |
15 | 1ba9ce751de4 |
hex | e0233ffbf5b |
15402625122139 has 2 divisors, whose sum is σ = 15402625122140. Its totient is φ = 15402625122138.
The previous prime is 15402625122127. The next prime is 15402625122217. The reversal of 15402625122139 is 93122152620451.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15402625122139 - 217 = 15402624991067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15402625122095 and 15402625122104.
It is not a weakly prime, because it can be changed into another prime (15402625122239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7701312561069 + 7701312561070.
It is an arithmetic number, because the mean of its divisors is an integer number (7701312561070).
Almost surely, 215402625122139 is an apocalyptic number.
15402625122139 is a deficient number, since it is larger than the sum of its proper divisors (1).
15402625122139 is an equidigital number, since it uses as much as digits as its factorization.
15402625122139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 15402625122139 in words is "fifteen trillion, four hundred two billion, six hundred twenty-five million, one hundred twenty-two thousand, one hundred thirty-nine".
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