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15402625122139 is a prime number
BaseRepresentation
bin1110000000100011001111…
…1111111011111101011011
32000112110212102112202211021
43200020303333323331123
54004324034012402024
652431511315143311
73146542260232663
oct340106377737533
960473772482737
1015402625122139
1149a9242377002
12188916bba4b37
138795cc688718
143b36c35791a3
151ba9ce751de4
hexe0233ffbf5b

15402625122139 has 2 divisors, whose sum is σ = 15402625122140. Its totient is φ = 15402625122138.

The previous prime is 15402625122127. The next prime is 15402625122217. The reversal of 15402625122139 is 93122152620451.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15402625122139 - 217 = 15402624991067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15402625122095 and 15402625122104.

It is not a weakly prime, because it can be changed into another prime (15402625122239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7701312561069 + 7701312561070.

It is an arithmetic number, because the mean of its divisors is an integer number (7701312561070).

Almost surely, 215402625122139 is an apocalyptic number.

15402625122139 is a deficient number, since it is larger than the sum of its proper divisors (1).

15402625122139 is an equidigital number, since it uses as much as digits as its factorization.

15402625122139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 15402625122139 in words is "fifteen trillion, four hundred two billion, six hundred twenty-five million, one hundred twenty-two thousand, one hundred thirty-nine".